SQLAlchemy ORM – 使用连接
SQLAlchemy ORM – 使用连接
现在我们有两个表,我们将看到如何同时在两个表上创建查询。为了在 Customer 和 Invoice 之间构建一个简单的隐式连接,我们可以使用 Query.filter() 将它们的相关列等同起来。下面,我们使用此方法一次加载 Customer 和 Invoice 实体 –
from sqlalchemy.orm import sessionmaker Session = sessionmaker(bind = engine) session = Session() for c, i in session.query(Customer, Invoice).filter(Customer.id == Invoice.custid).all(): print ("ID: {} Name: {} Invoice No: {} Amount: {}".format(c.id,c.name, i.invno, i.amount))
SQLAlchemy 发出的 SQL 表达式如下 –
SELECT customers.id AS customers_id, customers.name AS customers_name, customers.address AS customers_address, customers.email AS customers_email, invoices.id AS invoices_id, invoices.custid AS invoices_custid, invoices.invno AS invoices_invno, invoices.amount AS invoices_amount FROM customers, invoices WHERE customers.id = invoices.custid
以上代码行的结果如下 –
ID: 2 Name: Gopal Krishna Invoice No: 10 Amount: 15000 ID: 2 Name: Gopal Krishna Invoice No: 14 Amount: 3850 ID: 3 Name: Govind Pant Invoice No: 3 Amount: 10000 ID: 3 Name: Govind Pant Invoice No: 4 Amount: 5000 ID: 4 Name: Govind Kala Invoice No: 7 Amount: 12000 ID: 4 Name: Govind Kala Invoice No: 8 Amount: 8500 ID: 5 Name: Abdul Rahman Invoice No: 9 Amount: 15000 ID: 5 Name: Abdul Rahman Invoice No: 11 Amount: 6000
使用 Query.join() 方法可以轻松实现实际的 SQL JOIN 语法,如下所示 –
session.query(Customer).join(Invoice).filter(Invoice.amount == 8500).all()
join 的 SQL 表达式将显示在控制台上 –
SELECT customers.id AS customers_id, customers.name AS customers_name, customers.address AS customers_address, customers.email AS customers_email FROM customers JOIN invoices ON customers.id = invoices.custid WHERE invoices.amount = ?
我们可以使用 for 循环遍历结果 –
result = session.query(Customer).join(Invoice).filter(Invoice.amount == 8500) for row in result: for inv in row.invoices: print (row.id, row.name, inv.invno, inv.amount)
使用 8500 作为绑定参数,显示以下输出 –
4 Govind Kala 8 8500
Query.join() 知道如何在这些表之间进行连接,因为它们之间只有一个外键。如果没有外键或更多外键,Query.join() 在使用以下形式之一时效果更好 –
query.join(Invoice, id == Address.custid) | 显式条件 |
query.join(Customer.invoices) | 指定从左到右的关系 |
query.join(Invoice, Customer.invoices) | 相同,有明确的目标 |
query.join(‘invoices’) | 同样,使用字符串 |
类似地,可以使用 outerjoin() 函数来实现左外连接。
query.outerjoin(Customer.invoices)
subquery() 方法生成一个 SQL 表达式,表示嵌入在别名中的 SELECT 语句。
from sqlalchemy.sql import func stmt = session.query( Invoice.custid, func.count('*').label('invoice_count') ).group_by(Invoice.custid).subquery()
stmt 对象将包含一个 SQL 语句,如下所示 –
SELECT invoices.custid, count(:count_1) AS invoice_count FROM invoices GROUP BY invoices.custid
一旦我们有了我们的语句,它的行为就像一个表结构。语句中的列可通过名为 c 的属性访问,如下面的代码所示 –
for u, count in session.query(Customer, stmt.c.invoice_count).outerjoin(stmt, Customer.id == stmt.c.custid).order_by(Customer.id): print(u.name, count)
上面的 for 循环显示发票的名称计数如下 –
Arjun Pandit None Gopal Krishna 2 Govind Pant 2 Govind Kala 2 Abdul Rahman 2