PHP & MySQL – 更新记录示例
PHP & MySQL – 更新记录示例
PHP 使用mysqli query()或mysql_query()函数来更新 MySQL 表中的记录。此函数采用两个参数,成功时返回 TRUE,失败时返回 FALSE。
句法
$mysqli->query($sql,$resultmode)
Sr.No. | 参数及说明 |
---|---|
1 |
$sql 必需 – 用于更新 MySQL 表中记录的 SQL 查询。 |
2 |
$resultmode 可选 – 常量 MYSQLI_USE_RESULT 或 MYSQLI_STORE_RESULT 取决于所需的行为。默认情况下,使用 MYSQLI_STORE_RESULT。 |
例子
尝试以下示例来更新表中的记录 –
将以下示例复制并粘贴为 mysql_example.php –
<html> <head> <title>Updating MySQL Table</title> </head> <body> <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root@123'; $dbname = 'TUTORIALS'; $mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname); if($mysqli->connect_errno ) { printf("Connect failed: %s<br />", $mysqli->connect_error); exit(); } printf('Connected successfully.<br />'); if ($mysqli->query('UPDATE tutorials_tbl set tutorial_title = "Learning Java" where tutorial_id = 4')) { printf("Table tutorials_tbl updated successfully.<br />"); } if ($mysqli->errno) { printf("Could not update table: %s<br />", $mysqli->error); } $sql = "SELECT tutorial_id, tutorial_title, tutorial_author, submission_date FROM tutorials_tbl"; $result = $mysqli->query($sql); if ($result->num_rows > 0) { while($row = $result->fetch_assoc()) { printf("Id: %s, Title: %s, Author: %s, Date: %d <br />", $row["tutorial_id"], $row["tutorial_title"], $row["tutorial_author"], $row["submission_date"]); } } else { printf('No record found.<br />'); } mysqli_free_result($result); $mysqli->close(); ?> </body> </html>
输出
访问部署在 apache web 服务器上的 mysql_example.php 并验证输出。在这里,我们在运行选择脚本之前在表中输入了多条记录。
Connected successfully. Table tutorials_tbl updated successfully. Id: 1, Title: MySQL Tutorial, Author: Mahesh, Date: 2021 Id: 2, Title: HTML Tutorial, Author: Mahesh, Date: 2021 Id: 3, Title: PHP Tutorial, Author: Mahesh, Date: 2021 Id: 4, Title: Learning Java, Author: Mahesh, Date: 2021 Id: 5, Title: Apache Tutorial, Author: Suresh, Date: 2021